Originally Posted By Wimli (3 JUN 2003 12:44am)
Hey at least I'm making some progress now: I understand the question!

Originally Posted By MichalN (3 JUN 2003 1:01am)

That is a good first step towards the solution

 And don't worry, I'm not too sharp at 3am either.

Originally Posted By Andromus (3 JUN 2003 1:10am)
2. A cloud.
3. Bob and Dick bought a dog?
5. Hmmm....houses don't jump.

Originally Posted By Wimli (3 JUN 2003 1:14am)
I'm so proud of myself

(even if it's wrong, it's still a brilliant guess in my opinion when you are already with one leg in your bed.

)

Originally Posted By Wimli (3 JUN 2003 1:14am)


Hah! I was ready to go to bed and it suddenly hit me:

You mark each coin of a stack with the same colour and you this for all stacks (with a different colour for each stack).

Then you take one coin from the first stack, two from the second stack, three from the third stack, four from the fourth stack, and so on till ten coins from the tenth stack. Then you put all those coins on the scales and look at the result. Now the number behind the comma tells you how many fake coins are on the scales, as they weigh 0.1 more than the rest and so which stack contains only fake coins. So if the scales say 7,7 grams that means there are seven fake coins on the scales. Since you took seven coins from the seventh stack (and you recognize them because of the colour you used for the seventh stack) that's the one with ten false coins!!!

I'm so proud of myself

(even if it's wrong, it's still a brilliant guess in my opinion when you are already with one leg in your bed.

)

Originally Posted By MichalN (3 JUN 2003 1:15am)

Yep, that's the right solution! Told you it wasn't that hard

Originally Posted By MichalN (3 JUN 2003 1:14am)

All correct!

Now if I changed #5 to say "dog jumps higher than a house's roof", how can you still win? I can think of two ways

Originally Posted By Andromus (3 JUN 2003 1:23am)
I just need to get that dog up on the roof somehow and have him start jumping.

And I just thought of the other answer:  a house roof can't jump either, so the dog can win that way.

Originally Posted By MichalN (3 JUN 2003 1:36am)



That's not what I had in mind... if I had a dog standing on the ground next to a house, I could make the dog jump higher than the roof of that house is, and it has nothing to do with the fact that houses can't jump

Originally Posted By Andromus (3 JUN 2003 1:52am)
OK, if the house were a doghouse, that would work.

Originally Posted By MichalN (3 JUN 2003 1:54am)

Right, no one said the house had to be very tall

So... need any hints on the remaining riddles?

Originally Posted By Andromus (3 JUN 2003 2:04am)
Yeah, I guess so...the only answer I can think of for the first one is "Use the brakes!" but that's a little obvious.

The only thing I can think of regarding the apricots is to weigh a whole apricot, weigh the pot, and figure out from that how many apricots were used....although I can't figure out how she forgot how many apricots she used so soon. Or maybe there's something else about jam making that I'm not getting.....

Originally Posted By MichalN (3 JUN 2003 2:19am)

Just because an answer is obvious doesn't mean it's wrong

I accept that, and it'd be my answer as well. But there's a less obvious answer - where can you see cars, fire trucks, elephants, horses and more all going in the same in direction and at the same speed? And more importantly, in circles?

My answer would be "she remembers how many she'd put in". But in case she doesn't, there's a way to find out. Think of an apricot... and what it consists of.

Originally Posted By Andromus (3 JUN 2003 2:54am)
Sounds like a pretty strange place....but I'm still drawing a blank. If you want to leave it for someone else, that's fine, but I fold on this one.

Hmmm....you didn't say anything about her removing the pits. I suppose she could count those.

Originally Posted By MichalN (3 JUN 2003 3:13am)



For reference, there's still this unsolved math problem:

1. TWO x TWO = THREE
Each letter stands for one and only one digit, and no digit is represented by more than one letter. Can you work out what digits the letters in the above multiplication stand for so that the identity above is actually correct?

It's not as hard as it looks - there are far fewer possibilities than it seems. I mean, c'mon, it should be immediately obvious which digit 'T' stands for and what is the possible range of answers. Remember, I'm bad at math and I solved this one

Originally Posted By Andromus (3 JUN 2003 3:33am)
And you must know various computer langauges, so you really can't say you're bad at math....

Well, enough kvetching,...

138 X 138 = 19044?

Originally Posted By MichalN (3 JUN 2003 3:44am)


Interesting word. Is that from the German "quatsch"?

Originally Posted By MichalN (3 JUN 2003 3:13am)

It's not that much of an uncommon place... let's see if the ladies can come up with something

Originally Posted By Eva (3 JUN 2003 5:11am)
How about a circus?

Originally Posted By Eva (3 JUN 2003 10:46am)
But couldn't it be a circus - in theory, I mean? Is it a carousel, then?